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Javascript: split by this | that

How can I break a line like this

var str = "M50 0 L0 100 L100 100 L50 0 z M0 0 L100 0 L50 100 L0 0 Z"; var arr4String = str.split('z|Z');

I expect to get an array with three elements:

 ["M50 0 L0 100 L100 100 L50 0", "M0 0 L100 0 L50 100 L0 0", ""]
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6 answers

Use regex. Using the g flag, the entire line is searched from beginning to end so that it does not stop when it first accesses z|Z The i flag makes the search case insensitive.

  var str = "M50 0 L0 100 L100 100 L50 0 z M0 0 L100 0 L50 100 L0 0 Z"; var arr4String = str.split(/z/gi);
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If you want to split into a regular expression, you need to pass the regular expression to split as a parameter:

 var str = "M50 0 L0 100 L100 100 L50 0 z M0 0 L100 0 L50 100 L0 0 Z"; var arr4String = str.split(/z|Z/); ^ ^

It produces:

 ["M50 0 L0 100 L100 100 L50 0 ", " M0 0 L100 0 L50 100 L0 0 ", ""] ^ ^ ^

(note the extra spaces, as the regex does not remove them).

If you want to trim the results, you can use:

 ...split(/\s*z\s*/i);

or you can just bind:

 ...split(/z/i).map(function (val) { return val.trim(); });
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Here you can use the regular expression /\s*z\s*/i to separate:

 var str = "M50 0 L0 100 L100 100 L50 0 z M0 0 L100 0 L50 100 L0 0 Z"; var arr4String = str.split(/\s*z\s*/i); document.body.innerHTML = "<pre>" + JSON.stringify(arr4String,0,4) + "</pre>";

The regular expression /\s*z\s*/i will match zero or more spaces ( \s* ) before and after z (case-insensitive searches are performed using the /i modifier).

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You're close, but you want to use a regex instead of a string, which you can use using a slash instead of quotation marks ( /z|Z/ ).

However, just using this will not give you what you want. You really want a regular expression that removes the surrounding spaces around your z characters. Also, suppose if you pass a line containing "L100z200" , you do not want this to be split in the middle. To accomplish this, you can use \b to make sure that a word boundary exists. Here you are:

 var str = "M50 0 L0 100 L100 100 L50 0 z M0 0 L100 0 L50 100 L0 0 Z"; var arr4String = str.split(/\b\s*z\s*\b/i); console.log(arr4String); // Exactly: // ["M50 0 L0 100 L100 100 L50 0", "M0 0 L100 0 L50 100 L0 0", ""]
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 var arr4String = str.replace('z','Z').split('Z');
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For completeness only (may be faster than / z / i):

 var arr4String = str.split(/[zZ]/);
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