Pause ()

Question

The function is pause()blocked until a signal is received. Assuming that the process received a signal and pause (), whether the signal handler processes to the code following the call pause(), or the result of a sudden?

Example:

void sigusr1_handler() 
{
   // .. handler code
}

void main() 
{
   // .. bind handler to SIGUSR1

   pause(); // wait for SIGUSR1
   // some more code
}

Will "still some code" be executed after completion, sigusr1_handler() or is there a race condition? If so, what is the solution?
 I can think of nothing but lively, but then a pause will not be needed at all.

Answer 1

Quoting from the pause help page (2) :

pause() , . pause() -1, errno - EINTR.

, some more code.

Answer 2

; , , , .

, ; , , . , pause , , .

" ":

• write pipe read .
• sem_post sem_wait .
• sigwaitinfo sigtimedwait .

• pause, :

  while(!signal_handler_finished) pause();
  

  signal_handler_finished volatile sig_atomic_t .