Python: how to get the * full * name of the function I am in

Question

Is there a way to get the following code:

import traceback

def log(message):
    print "%s: %s" %(traceback.extract_stack()[0:-1][-1][2], message)

def f1():
    log("hello")

class cls(object):
    def f1(self):
        log("hi there")

f1()
mycls = cls()
mycls.f1()

displayed:

f1: hello
cls.f1: hi there

instead:

f1: hello
f1: hi there

?

I tried to use the check module, but was not successful ...

Julien

EDIT:

It indicates that the "log" function can retrieve the caller (using tracing, checking, or any average value).

I do not want to pass the class name or anything other than a "message" to the "log" function.

Answer 1

So, I finally came up with this method:

#!/usr/bin/env python3

def log(message):
    import inspect
    import gc
    code = inspect.currentframe().f_back.f_code
    func = [obj for  obj in  gc.get_referrers(code) if inspect.isfunction(obj)][0]
    print(func.__qualname__, message)

He needs python3 so that __qualname__ can be used.

Answer 2

inspect , traceback , , . , self, /:

import inspect

class cls(object):
    def f1(self):
        this_class_name = type(self).__name__
        this_func_name = inspect.currentframe().f_code.co_name
        print(this_class_name, this_func_name)

mycls = cls()
mycls.f1()