__call, __callStatic and call scope in PHP

Question

I recently read about calling the scope operator and scope operator (: :) in PHP. There are two options: instance call and static call. Consider the following list:

<?php

class A {
    public function __call($method, $parameters) {
        echo "I'm the __call() magic method".PHP_EOL;
    }

    public static function __callStatic($method, $parameters) {
        echo "I'm the __callStatic() magic method".PHP_EOL;
    }
}

class B extends A {
    public function bar() {
        A::foo();
    }
}

class C {
    public function bar() {
        A::foo();
    }
}

A::foo();
(new A)->foo();

B::bar();
(new B)->bar();

C::bar();
(new C)->bar();

The result of execution (PHP 5.4.9-4ubuntu2.2) is:

I'm the __callStatic() magic method
I'm the __call() magic method
I'm the __callStatic() magic method
I'm the __call() magic method
I'm the __callStatic() magic method
I'm the __callStatic() magic method

I do not understand why to (new C)->bar();execute __callStatic()from A? An instance call must be made in the context of the bar () method, right? Is this a feature of PHP?

Addition1:

Also, if I don’t use magic methods and explicitly call, everything works as expected:

<?php

class A {
    public function foo() {
        echo "I'm the foo() method of A class".PHP_EOL;
        echo 'Current class of $this is '.get_class($this).PHP_EOL;
        echo 'Called class is '.get_called_class().PHP_EOL;
    }
}

class B {
    public function bar() {
        A::foo();
    }
}

(new B)->bar();

Result for this:

I'm the foo() method of A class
Current class of $this is B
Called class is B

Answer 1

In the method bar()in Cyou have A::foo();:

public function bar() {
    A::foo();
}

A, C extend A, :: , A::foo(). foo() A, __callStatic().

, A, A:

class C {
    public function bar() {
        $aInstance = new A();
        $aInstance->foo();
    }
}

Answer 2

, A. ,

 class B extends A

, new B A->foo.

C A, A.