How to create a loop in JavaScript?

Question

How to create a loop in JavaScript?

Answer 1

For cycles

for (i = startValue; i <= endValue; i++) {
    // Before the loop: i is set to startValue
    // After each iteration of the loop: i++ is executed
    // The loop continues as long as i <= endValue is true
}

For ... in cycles

for (i in things) {
    // If things is an array, i will usually contain the array keys *not advised*
    // If things is an object, i will contain the member names
    // Either way, access values using: things[i]
}

It is bad practice to use loops for...into repeat arrays. This is contrary to the ECMA 262 standard and can cause problems when non-standard attributes or methods are added to an Array object, for example. Prototype . (Thanks to Chase Seibert for pointing this out in the comments)

Bye cycles

while (myCondition) {
    // The loop will continue until myCondition is false
}

Answer 2

Here is an example for loop:

We have an array of node elements .

for(var i = 0; i< nodes.length; i++){
    var node = nodes[i];
    alert(node);
}

Answer 3

; . http://www.robertnyman.com/2008/04/11/javascript-loop-performance/

Answer 4

(while() ..., do ... while(), for() ...), , , .

:

// set the initial value
var loopCounter = 3;

// the body of the loop
function loop() {

    // this is only to show something, done in the loop
    document.write(loopCounter + '<br>');

    // decrease the loopCounter, to prevent running forever
    loopCounter--;

    // test loopCounter and if truthy call loop() again 
    loopCounter && loop();
}

// invoke the loop
loop();

Needless to say, this structure is often used in conjunction with the return value, so this is a small example of how to deal with a value that is not available the first time, but at the end of the recursion:

function f(n) {
    // return values for 3 to 1
    //       n   -n  ~-n   !~-n   +!~-n   return
    // conv int neg bitnot  not  number 
    //       3   -3   2    false    0    3 * f(2)
    //       2   -2   1    false    0    2 * f(1)
    //       1   -1   0     true    1        1
    // so it takes a positive integer and do some conversion like changed sign, apply
    // bitwise not, do logical not and cast it to number. if this value is then
    // truthy, then return the value. if not, then return the product of the given
    // value and the return value of the call with the decreased number
    return +!~-n || n * f(n - 1);
}

document.write(f(7));

Run code

Answer 5

The loop in JavaScript looks like this:

for (var = startvalue; var <= endvalue; var = var + increment) {
    // code to be executed
}