Deep xml serialize structure

Question

I have the class and structure shown below. If I serialize the class as using xmlserializer, I get:

<Test>
<TestNumber1> 5 </ TestNumber1>
<InnerTest / ">
</ Test>

what is the easiest way to serialize InnerTest properly (preferably using xmlserializer) without providing the Number a setter property?

Thanks Nick

public class Test 
{ 
    private InnerTest innerTest; 
    private int testNumber; 


    public Test() 
    { 
        this.innerTest = new InnerTest(); 
        this.testNumber = 5; 
    } 


    public int TestNumber1 
    { 
        get { return this.testNumber; } 
        set { this.testNumber = value;} 
    } 


    public InnerTest InnerTest 
    { 
        get { return this.innerTest; } 
        set { this.innerTest = value;} 
    } 


} 


public struct InnerTest 
{ 
    private int number; 


    public InnerTest(int number) 
    { 
        this.number = number; 
    } 
    public int Number{get { return number; }} 
} 

Answer 1

, IXmlSerializable XmlSerializer, , get/set , - , ( - , , DateTime, ).

, , .NET , DataContractSerializer, , (, DataMemberAttribute ). XML- ( - , !), , .

( -, , XmlSerializer , DataContractSerializer, , , .)

Answer 2

, DataContractSerializer (.NET 3.0), - :

[DataMember]
public int TestNumber1 
{ 
    get { return this.testNumber; } 
    set { this.testNumber = value;} 
} 

// note **not** a data-member
public InnerTest InnerTest 
{ 
    get { return this.innerTest; } 
    set { this.innerTest = value;} 
} 

[DataMember]
private int InnerTestValue
{
    get {return innerTest.Number;}
    set {innerTest = new InnerTest(value);}
}

. XmlSerializer, InnerTestValue ( [Browsable(false), EditorBrowsable(EditorBrowsableState.Never)] - ).

, ... . , , . , [de] ( ) .

- POCO, , ; , .

Answer 3

, , IXmlSerializable.

, , - . XmlSerializer , , ( ), , , .

, (, DateTime)... , XmlSerializer.

Answer 4

XmlSerializer :

Test test = new Test { TestNumber1 = 5 };

XmlSerializer xmlSer = new XmlSerializer(typeof(Test));
MemoryStream memStm = new MemoryStream();

xmlSer.Serialize(memStm, test);

, ( ):

StreamReader stmR = new StreamReader(memStm);
memStm.Position = 0;
string output = stmR.ReadToEnd();

If you do nothing, all the public properties of the class you are serializing will display as XML elements ..... in your resulting XML.

There are many attributes, such as [XmlIgnore] and many others, to configure them if necessary.

Enjoy it!