Geek Answers Handbook

Why is this not a valid circuit for Rx?

I am using YAML as the configuration file format for a Python project.

I recently found Rx to be the only schema validator available for Python and YAML.: - / Kwalify works with YAML, but it is only for Ruby and Java . :(

I read their missing documentation all day and just can't write the right schema to represent my file structure. Help?

I have the following YAML configuration file:

cmd:
  exec: mycmd
  aliases: [my, cmd]
  filter:
    sms: 'regex .*'

load:
  exec: load
  filter:
    sms: 'load: .*$'

echo:
  exec: echo %

. , (cmd, load echo, ) , , , . "exec" - ; "" "" , . , , . Rx?

( YAML), Rx :

type: //rec
required:
  type: //rec
  required:
    exec: //str
  optional:
    aliases:
      type: //arr
      contents: //str
      length: {min: 1, max: 10}
    filter:
      type: //rec
      optional:
        sms: //str
        email: //str
        all: //str

IPython :

/Rx.py in make_schema(self, schema)
     68       raise Error('invalid schema argument to make_schema')
     69
---> 70     uri = self.expand_uri(schema["type"])
     71
     72     if not self.type_registry.get(uri): raise "unknown type %s" % uri

KeyError: 'type'

, "" -.: -S

?

, ... ?

,

+5
1

:

type: //map
values:
  type: //rec
  required:
    exec: //str
  optional:
    aliases:
      type: //arr
      contents: //str
      length: {min: 1, max: 10}
    filter:
      type: //rec
      optional:
        sms: //str
        email: //str
        all: //str

, rec , "" "".

+4

More articles:


All Articles