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Filter a table from <select> input using jQuery

I am trying to filter a table from alphabetical input <select>using jQuery.

I have a first and last name in two columns of a table, and I would like to filter the rows with one of them.

I have a selected input configured like this:

<select>
    <option value="A">A</option>
    <option value="B">B</option>
    <option value="C">C</option>
    ...
</select>

and I would like to filter this table:

<tr>
    <td>Joe</td>
    <td>Schmoe</td>
    <td>$2482.79</td>
    <td>172.78.200.124</td>
    <td>http://gmail.com</td>
</tr>
<tr>
    <td>John</td>
    <td>Doe</td>
    <td>$2776.09</td>
    <td>119.232.182.142</td>
    <td>http://www.example.com</td>
</tr>

How do I configure table filtering using jQuery?

+5
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5 answers

This will work if you only have one selection table and one table that will look like your example

$(document).ready(function($) {
    var rows = $('table tr').each(function() {
        var row = $(this);
        var columns = row.children('td');

        row.data('name-chars', [
            columns.eq(0).html()[0].toUpperCase(),
            columns.eq(1).html()[0].toUpperCase(),
        ]);
    });

    $('select').change(function() {
        var char = $(this).val().toUpperCase();

        rows.each(function() {
            var row = $(this);
            var chars_to_match = row.data('name-chars');
            if($.inArray(char, chars_to_match) > -1) {
                row.show();
            }
            else {
                row.hide();
            }
        });
    });
});
+6
source

I came up with this. Pretty similar to what Elzo came up with, but restricts it to the first two columns of the table.

 $('select').change( function(e) { 
   var letter = $(this).val();
     if (letter === 'ALL') {
         $ ('tr').show ();
     }
     else {
         $('tr').each( function(rowIdx,tr) {
             $(this).hide().find('td').each( function(idx, td) {
                 if( idx === 0 || idx === 1) {
                     var check = $(this).text();
                     if (check && check.indexOf(letter) == 0) {
                         $(tr).show();
                     }
                 }
             });             

         });
     }             
 });

, , - , .

"ALL", .

+2

. y $(y).

$('tr').hide();
$('select').change( function(){
    var letter = $(this).val();
    var dataset = $('#tableID').find('td');
    $.each(dataset, function(x, y){
        if( y.substr(0,1) == letter){
            y.parent().show();
        }
    });
});

Edit

@SolutionYogi. . , :

var dataset = $('#tableID').find('tr').children('td').slice(0,1);

.

2

. , , .

$('tr').hide();
$('select').change( function(){
    var letter = $(this).val();
    var dataset = $('#tableID').find('tr');
        $.each(dataset, function(x, y){
            var data = $(y).children().slice(0,2);
                $.each(data, function(a, b){
                    if( $(b).html().substr(0,2) == letter){
                        $(b).parent().show();
                    }
             });
       });
});
0

sel, - , . eq (0), . trs.

var selSelection = $("#sel").val();
if(!selSelection) $("#tab tr").show();
else $("#tab tr").show().filter(function(index){
    return $("td:eq(0)", this).html().indexOf(selSelection) == -1;
}).hide();
0

$( "td: not (: ('" + input_value + "'))" ). remove();

... ?

0

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