Skip type dynamically to <T>

Question

I have such a situation ...

object myRoledata  = List<Roles>() --> (some list or Ienumerable type)

Now I have a generic method that creates an XML object from List<T>- Something like this ..

public string GetXML<T>(object listdata)  
{  
    List<T> objLists = (List<T>)Convert.ChangeType(listData, typeof(List<T>));  
    foreach(var obj in listdata)   
    {  
        //logic to create xml  
    }  
}

Now, to run this method, I have to do like this:

string xml = GetXML<Roles>(myRoledata);

Now I do not know what Typecan come to me to pass a method GetXML. I have a method that will call GetXMLfor different ones Type, for example. Roles, Usersetc.

now i can get Typeinside List<>like this

Type genericType = obj.GetType().GetGenericArguments()[0];

but can't pass it like that

string xml = GetXML<genericType>(myRoledata);

Is there any way in which I can pass any method genericTypesto GetXML?

Answer 1

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:

public string GetXML(IEnumerable listdata) {  
    foreach(object obj in listdata)   
        //logic to create xml  
}

... IEnumerable, "" :

public string GetXML(IEnumerable<object> listdata) {  
    foreach(object obj in listdata)   
        //logic to create xml  
}

..., IEnumerable GetXML(someEnumerable.Cast<object>()) # 4.0 .

, .GetType() ( ):

public string GetXML(Type elementType, IEnumerable<object> listdata) {  
    foreach(object obj in listdata)   
        //logic to create xml  
}

public string GetXML<T>(IEnumerable<T> listdata) {
    return GetXML(typeof(T),listdata.Cast<object>());
}

, XML, , , : , - XElement xml .

Answer 2

;

typeof(SomeClass).GetMethod("GetXML").MakeGenericMethod(genericType)
         .Invoke(inst, new object[] {myRoleData});

inst null, , this ( GetType() typeof(SomeClass)),

Answer 3

listdata <T> ,

public string GetXML<T>(List<T> listdata)

, , .

EDIT: , IEnumerable, . ,

public string GetXML<T>(IEnumerable<T> listdata)

Answer 4

, :

public string GetXML<T>(IEnumerable<T> listdata)  
{  
    foreach(var obj in listdata)   
    {  
        //logic to create xml  
    }  
}

:

List<Role> myList;
GetXML(myList);

, , , , , .

Answer 5

, . Type.MakeGenericType MethodInfo.MakeGenericMethod. , , .

GetGenericArguments() . .

Btw: , - XML. , , .; -)