How to find the size of a multidimensional array in C

Question

I declared a two-dimensional array as follows:

char *array[][3] = {
    {"a", "b", "c"},
    {"d", "e", "f"},
    {"u", "v", "w"},
    {"x", "y", "z"}};

How to find out the first dimension?

Answer 1

sizeof array / sizeof array [0]

Example: ^*

#include <stdio.h>

int main(void) {
  int array[4];

    printf("%zd\n", sizeof array / sizeof array[0]);
    printf("%zd\n", sizeof (int));
    printf("%ld\n", (long)(sizeof array / sizeof array[0]));
    return 0;
}

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Answer 2

:

sizeof(array) / sizeof(char*) / 3

?

, (char *) (3).

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