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DataTemplate-view View with MVVM

I have a container view that looks something like this.

<UserControl x:Class="Views.ContainerView">
    <UserControl.Resources>
        <ResourceDictionary>
            <DataTemplate DataType="{x:Type viewmodels:AViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:BViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:CViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:DViewModel}">
                <views:MyView />
            </DataTemplate>
        </ResourceDictionary>
    </UserControl.Resources>
    <Grid>
        <ListBox ItemsSource="{Binding Path=AvailableViewModels}" 
            SelectedItem="{Binding Path=CurrentViewModel}" 
            IsSynchronizedWithCurrentItem="True" />
        <ContentControl Content="{Binding Path=CurrentViewModel}" />
    </Grid>
</UserControl>

All my viewmodels inherit BaseViewModel, so I turned my eyes on this

<UserControl x:Class="Views.ContainerView">
    <UserControl.Resources>
        <ResourceDictionary>
            <DataTemplate DataType="{x:Type viewmodels:BaseViewModel}">
                <views:MyView />
            </DataTemplate>
        </ResourceDictionary>
    </UserControl.Resources>
    <StackPanel>
        <ListBox ItemsSource="{Binding Path=AvailableViewModels}" 
            SelectedItem="{Binding Path=CurrentViewModel}" 
            IsSynchronizedWithCurrentItem="True" />
        <ContentControl Content="{Binding Path=CurrentViewModel}" />
    </StackPanel>
</UserControl>

thinking that this will create an instance of only one MyView and just rebuild the viewmodel when ListBox.SelectedItem changes. Do I understand this behavior correctly? Is this the preferred practice? How can I verify that I will not mix up memory when switching between views?

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2 answers

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+2

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