Like this:
from operator import itemgetter
l = sorted(l, key=itemgetter('time'), reverse=True)
Or:
l = sorted(l, key=lambda a: a['time'], reverse=True)
output:
[{'time': 66}, {'time': 33}, {'time': 11}]
If you do not want to keep the original order, you can use your_list.sortthat changes the original list instead of creating a copy, for examplesorted(your_list)
l.sort(key=lambda a: a['time'], reverse=True)