C # XML-RPC and Python RPC Server

Question

On my server, I use the standard Python example (with the optional Hello World Method), and on the client side, I use the XML-RPC.NET library in C #. But every time I start my client, I get an exception that the method was not found. Any ideas how to fix this.

thanks!

Python:

from SimpleXMLRPCServer import SimpleXMLRPCServer
from SimpleXMLRPCServer import SimpleXMLRPCRequestHandler

# Restrict to a particular path.
class RequestHandler(SimpleXMLRPCRequestHandler):
    rpc_paths = ('/RPC2',)

# Create server
server = SimpleXMLRPCServer(("", 8000),
                            requestHandler=RequestHandler)
server.register_introspection_functions()

# Register pow() function; this will use the value of
# pow.__name__ as the name, which is just 'pow'.
server.register_function(pow)

# Register a function under a different name
def adder_function(x,y):
    return x + y
server.register_function(adder_function, 'add')

def HelloWorld():
        return "Hello Henrik"

server.register_function(HelloWorld,'HelloWorld')

# Register an instance; all the methods of the instance are
# published as XML-RPC methods (in this case, just 'div').
class MyFuncs:
    def div(self, x, y):
        return x // y

server.register_instance(MyFuncs())

# Run the server main loop
server.serve_forever()

FROM#

namespace XMLRPC_Test
{
    [XmlRpcUrl("http://188.40.xxx.xxx:8000")]
    public interface HelloWorld : IXmlRpcProxy
    {
        [XmlRpcMethod]
        String HelloWorld();
    }
    [XmlRpcUrl("http://188.40.xxx.xxx:8000")]
    public interface add : IXmlRpcProxy
    {
        [XmlRpcMethod]
        int add(int x, int y);
    } 
    [XmlRpcUrl("http://188.40.xxx.xxx:8000")]
    public interface listMethods : IXmlRpcProxy
    {
        [XmlRpcMethod("system.listMethods")]  
        String listMethods();
    } 

    class Program
    {
        static void Main(string[] args)
        {
            listMethods proxy = XmlRpcProxyGen.Create<listMethods>();
            Console.WriteLine(proxy.listMethods());
            Console.ReadLine();
        }
    }
}

Answer 1

Does it work if you change the advertisement to this?

[XmlRpcUrl("http://188.40.xxx.xxx:8000/RPC2")]

From Python Docs :

SimpleXMLRPCRequestHandler.rpc_paths

, , URL- XML-RPC. , , HTTP 404 " ". , . : ('/', '/RPC2').