Geek Answers Handbook

How to select last child row of parent / child relationship using SQL

Using only SQL (MySQL), I would like to select each of the last child rows of the parent child relationship, where the child rows are ordered by timestamp.

For example, using tables invoicesand invoice_items, I want to get the newest (i.e. the most recent temporary) entries invoice_itemsfor each, invoicerespectively.

--------------------------
|Invoices                |
--------------------------
|invoice_id| other fields|
--------------------------
| 1        | ...         |
--------------------------
| 2        | ...         |
--------------------------
| 3        | ...         |
--------------------------

--------------------------------------------
|Invoice_Items                             |
--------------------------------------------
| id | invoice_id | invoice_item_timestamp |
--------------------------------------------
| 1  | 1            | 2009-12-01 10:00:00  |
--------------------------------------------
| 2  | 1            | 2009-12-01 10:01:00  |
--------------------------------------------
| 3  | 1            | 2009-12-01 10:02:00  |
--------------------------------------------
| 4  | 2            | 2009-12-01 9:00:00   |
--------------------------------------------
| 5  | 3            | 2009-12-02 08:30:00  |
--------------------------------------------
| 6  | 3            | 2009-12-03 08:31:00  |
--------------------------------------------

What is the best SQL syntax for creating a result set that looks something like this:

-----------------------------------------------------
|invoice_id| invoice_item_id |invoice_item_timestamp|
---------------------------------------------------
| 1        | 3               | 2009-12-01 10:02:00  |
| 2        | 4               | 2009-12-01 09:00:00  |
| 3        | 6               | 2009-12-03 08:31:00  |
-----------------------------------------------------
+5
source share
4 answers
SELECT i.*,it.* 
FROM invoices i
INNER JOIN (
 SELECT invoice_id, MAX(invoice_item_timestamp) 
 FROM invoice_items
 GROUP BY invoice_id
) it ON (i.invoice_id=it.invoice_id)
+14
source

I do not use MySQL, but you get the idea:

select 
  invoices in

  inner join invoice_items it
  on in.invoice_id = it.invoice_id
  and invoice_item.invoice_item_id =
     (select max(invoice_item_id) from invoice_item 
        where invoice_id = in.invoice_id)

... if there are no duplicates invoice_item_id and invoice_id in the invoice_item table.

+1

, - :

select i.invoice_id, ii.id, ii.invoice_item_timestamp from invoices i left join invoice_items ii on ii.invoice_id = i.invoice_id
 where ii.invoice_item_timestamp = 
   (select max(ii2.invoice_item_timestamp) from invoice_items ii2 where ii2.invoice_id = ii.invoice_id)
0

You can try this (unverified):

SELECT a.*
FROM Invoices a, invoice_items b
WHERE a.invoice_id = b.invoice_id 
ORDER BY invoice_item_timestamp DESC
LIMIT 1
-1
source

More articles:


All Articles