C ++ empty class or typedef

Question

I am currently using something similar in my code:

class B : public A<C> { };

Wouldn't it be better to use typedef?

typedef A<C> B;

Answer 1

It depends. If you want to A<C>, and Bhave been excellent, but related types Bshould expand A<C>. If you want them to be identical, you should use typedef. Can you provide more context?

Answer 2

It depends on what you want. If you use different classes to configure template metaprograms, it’s better to create one B.

, , typedef, .

Answer 3

, , typedef.

Answer 4

. , typedef :

typedef A<C> B;
func(B param) {...}
...
A<C> var;
func(var);

Answer 5

, , , A<C>. , typedef - . , , .

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Answer 6

, , .

C ++ typedefs are not "strong", which basically means that Bthey A<C>will be of the same type. If you want to distinguish between two, use a class.

Various options for a strong typedef can be found on the Internet, boost one , for example.

Answer 7

For completeness, I want to add one more point: C

class B : public A<C> { };

you can easily forward ad B:

class B;
void func(B param);