How to do it:
template<typename Metafun, typename Tuple>
struct mod;
template<typename Metafun, template<typename...> class Tuple, typename ...Types>
struct mod<Metafun, Tuple<Types...>> {
typedef Tuple<typename Metafun::template apply<Types>::type...>
type;
};
Then
typedef std::tuple<int, bool> tuple_foo;
struct add_pointer {
template<typename T>
struct apply { typedef T *type; };
};
typedef mod<add_pointer, tuple_foo>::type tuple_ptrfoo;
This is the use of the metafunction class by packaging applyin a non-template. This allows you to pass it to C ++ 03 templates (which cannot accept templates with arbitrary parameters, just by doing template<typename...> class X). You can, of course, accept a pure metafound (not a class) too
template<template<typename...> class Metafun, typename Tuple>
struct mod;
template<template<typename...> class Metafun, template<typename...> class Tuple,
typename ...Types>
struct mod<Metafun, Tuple<Types...>> {
typedef Tuple<typename Metafun<Types>::type...>
type;
};
And use the template std::add_pointer
typedef mod<std::add_pointer, tuple_foo>::type tuple_ptrfoo;
,
template<template<typename...> class Metafun>
struct ToClass {
template<typename ... T>
struct apply { typedef Metafun<T...> type; };
};
typedef mod<ToClass<std::add_pointer>, tuple_foo>::type tuple_ptrfoo;
, .