How to read a string in java

Question

I have this line:

<meis xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" uri="localhost/naro-nei" onded="flpSW531213" identi="lemenia" id="75" lastStop="bendi" xsi:noNamespaceSchemaLocation="http://localhost/xsd/postat.xsd xsd/postat.xsd">

How can I get the value of a property lastStopin JAVA?

This regular expression worked when testing at http://www.myregexp.com/

But when I try in java, I don't see the consistent text, this is how I tried:

import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class SimpleRegexTest {
    public static void main(String[] args) {
        String sampleText = "<meis xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" uri=\"localhost/naro-nei\" onded=\"flpSW531213\" identi=\"lemenia\" id=\"75\" lastStop=\"bendi\" xsi:noNamespaceSchemaLocation=\"http://localhost/xsd/postat.xsd xsd/postat.xsd\">";
        String sampleRegex = "(?<=lastStop=[\"']?)[^\"']*";
        Pattern p = Pattern.compile(sampleRegex);
        Matcher m = p.matcher(sampleText);
        if (m.find()) {
            String matchedText = m.group();
            System.out.println("matched [" + matchedText + "]");
        } else {
            System.out.println("didn’t match");
        }
    }
}

Perhaps the problem is that I am using escape char in my test, but the real line has no way out inside.

UPDATE

Does anyone know why this does not work when used in java? or how to make it work?

Answer 1

(?<=lastStop=[\"']?)[^\"]+

Answer 2

, , , - * [^\"']*. Lookbehind " lastStop=", , : [\"']?. , , .

* +, , . Lookbehind , [^\"']+ . , lookbehind , . , :

String sampleRegex = "lastStop=[\"']?([^\"']*)";
Pattern p = Pattern.compile(sampleRegex);
Matcher m = p.matcher(sampleText);
if (m.find()) {
    String matchedText = m.group(1);
    System.out.println("matched [" + matchedText + "]");
} else {
    System.out.println("didn’t match");
}

, . , , , . -, , . , .