I have a C ++ class that has the following methods:
class Bar {
...
const Foo& getFoo() const;
void setFoo(const Foo&);
};
where the class Foocan be converted to std::string(it has an implicit constructor from std::stringand a translation operator std::string).
I define a Boost.Python wrapper class, which, among other things, defines a property based on the previous two functions:
class_<Bar>("Bar")
...
.add_property(
"foo",
make_function(
&Bar::getFoo,
return_value_policy<return_by_value>()),
&Bar::setFoo)
...
I also mark the class as convertible to / from std::string.
implicitly_convertible<std::string, Foo>();
implicitly_convertible<Foo, std::string>();
But at runtime, I still get a conversion error trying to access this property:
TypeError: No to_python (by-value) converter found for C++ type: Foo
How to achieve conversion without too many wrapper function templates? (I already have all the conversion functions in the class Foo, so duplication is undesirable.