I study ASM 8086 theoretically in high school.And when I do this:MOV BX,[SI]SI + 1 goes to BH or BL?Thank: -)
MOV BX,[SI]
The byte in the memory SI + 1will be stored in the register BH, because x86 is a bit endian .
SI + 1
BH
I think your question is about endianness x86, and the answer is that it is unimportant: the byte to the SI address goes to BL. The byte in SI + 1 goes to BH.