Skipping Number, Number.prototype.format

Question

I saw this format function referenced on several sites, but not one of them has an explicit example on how to pass a number to a function.

I tried '12345'.format (' 0.00 '), which, it seems to me, should be written, but it gives me an error that the object does not support the property or method. I also tried Number ('12345'). Format ('0.00'); var num = '12345' // num.format ('0.00'); format ('0.00', '12345') and even tried to use numbers instead of lines 12345.format (0.00). Did I miss something really obvious here?

A copy of the function for the link is included, so you do not need to go to the site (with all the fragments filled).

/**
 * I ♥ Google
 */
String.prototype.stripNonNumeric = function() {
    var str = this + '';
    var rgx = /^\d|\.|-$/;
    var out = '';
    for( var i = 0; i < str.length; i++ ) {
        if( rgx.test( str.charAt(i) ) ) {
            if( !( ( str.charAt(i) == '.' && out.indexOf( '.' ) != -1 ) ||
            ( str.charAt(i) == '-' && out.length != 0 ) ) ) {
                out += str.charAt(i);
            }
        }
    }
    return out;
};

/**
 * Formats the number according to the 'format' string; adherses to the american number standard where a comma is inserted after every 3 digits.
 *  note: there should be only 1 contiguous number in the format, where a number consists of digits, period, and commas
 *        any other characters can be wrapped around this number, including '$', '%', or text
 *        examples (123456.789):
 *          '0' - (123456) show only digits, no precision
 *          '0.00' - (123456.78) show only digits, 2 precision
 *          '0.0000' - (123456.7890) show only digits, 4 precision
 *          '0,000' - (123,456) show comma and digits, no precision
 *          '0,000.00' - (123,456.78) show comma and digits, 2 precision
 *          '0,0.00' - (123,456.78) shortcut method, show comma and digits, 2 precision
 *
 * @method format
 * @param format {string} the way you would like to format this text
 * @return {string} the formatted number
 * @public
 */
Number.prototype.format = function(format) {
    if (!(typeof format == "string")) {return '';} // sanity check

    var hasComma = -1 < format.indexOf(','),
        psplit = format.stripNonNumeric().split('.'),
        that = this;

    // compute precision
    if (1 < psplit.length) {
        // fix number precision
        that = that.toFixed(psplit[1].length);
    }
    // error: too many periods
    else if (2 < psplit.length) {
        throw('NumberFormatException: invalid format, formats should have no more than 1 period: ' + format);
    }
    // remove precision
    else {
        that = that.toFixed(0);
    }

    // get the string now that precision is correct
    var fnum = that.toString();

    // format has comma, then compute commas
    if (hasComma) {
        // remove precision for computation
        psplit = fnum.split('.');

        var cnum = psplit[0],
            parr = [],
            j = cnum.length,
            m = Math.floor(j / 3),
            n = cnum.length % 3 || 3; // n cannot be ZERO or causes infinite loop

        // break the number into chunks of 3 digits; first chunk may be less than 3
        for (var i = 0; i < j; i += n) {
            if (i != 0) {n = 3;}
            parr[parr.length] = cnum.substr(i, n);
            m -= 1;
        }

        // put chunks back together, separated by comma
        fnum = parr.join(',');

        // add the precision back in
        if (psplit[1]) {fnum += '.' + psplit[1];}
    }

    // replace the number portion of the format with fnum
    return format.replace(/[\d,?\.?]+/, fnum);
};

Answer 1

- isType stripNonNumeric. , Number, :

(42).format('0.00');

var a = 42;
a.format('0.00');

'12345'.format('0.00') '12345' , .

question , , , - ​​ .. , - , . , .. hahahaha