Scala, where the type of the second parameter is equal to the part of the general type from the first parameter

Question

I want to create a specific generic method in Scala. It takes two parameters. The first is a generic Java interface type (it is from a JPA criteria request). Currently, it looks like this:

def genericFind(attribute:SingularAttribute[Person, _], value:Object) {
  ...
}

// The Java Interface which is the type of the first parameter in my find-method:
public interface SingularAttribute<X, T> extends Attribute<X, T>, Bindable<T>

Now I want to achieve the following: The value is currently of type java.lang.Object. But I want to make it more specific. The value must be of the same type as the placeholder "_" from the first parameter (and therefore represents "T" in the Java interface).

How is this possible and how?

BTW Sorry for the stupid question (any suggestions?)

EDIT: Added an additional example that can make the problem clearer:

// A practical example how the Scala method could be called 

// Java class:
public class Person_ {
  public static volatile SingularAttribute<Person, Long> id;
}

// Calling the method from Scala:
genericFind(Person_.id, Long)

Answer 1

( Scala):

def genericFind[T](attribute:SingularAttribute[Person, T], value:T) {
  ...
}