Receive multiple IMAP messages at once

Question

The examples that I saw when downloading emails via IMAP using python do a search, and then make a request for each message identifier in the results. I want to speed up the process by pulling them all out right away.

Answer 1

RFC 3501 says that fetch accepts a set of sequences, but I have not seen a definition for this, and this example uses the range form (2: 4 = messages 2, 3, and 4). I realized that a comma separated list of identifiers works. In python with imaplib, I have something like:

    status, email_ids = con.search(None, query)
    if status != 'OK':
        raise Exception("Error running imap search for spinvox messages: "
                        "%s" % status)

    fetch_ids = ','.join(email_ids[0].split())
    status, data = con.fetch(fetch_ids, '(RFC822.HEADER BODY.PEEK[1])')
    if status != 'OK':
        raise Exception("Error running imap fetch for spinvox message: "
                        "%s" % status)
    for i in range(len(email_ids[0].split())):
        header_msg = email.message_from_string(data[i * 3 + 0][1])
        subject = header_msg['Subject'],
        date = header_msg['Date'],
        body = data[i * 3 + 1][1] # includes some mime multipart junk

Answer 2

, 1 .

import imaplib
import email

obj = imaplib.IMAP4_SSL('imap.gmail.com', 993)
obj.login('username', 'password')
obj.select('folder_name')
resp,data = obj.uid('FETCH', '1:*' , '(RFC822.HEADER)')
messages = [data[i][1].strip() + "\r\nSize:" + data[i][0].split()[4] + "\r\nUID:" + data[i][0].split()[2]  for i in xrange(0, len(data), 2)]
for msg in messages:
    msg_str = email.message_from_string(msg)
    message_id = msg_str.get('Message-ID')