Apart from one example in the docs, I cannot find documentation on exactly how django selects a name with which to access the child from the parent. In their example, they do the following:
class Place(models.Model):
name = models.CharField(max_length=50)
address = models.CharField(max_length=80)
def __unicode__(self):
return u"%s the place" % self.name
class Restaurant(models.Model):
place = models.OneToOneField(Place, primary_key=True)
serves_hot_dogs = models.BooleanField()
serves_pizza = models.BooleanField()
def __unicode__(self):
return u"%s the restaurant" % self.place.name
>>> p1 = Place(name='Demon Dogs', address='944 W. Fullerton')
>>> p1.save()
>>> p2 = Place(name='Ace Hardware', address='1013 N. Ashland')
>>> p2.save()
>>> r = Restaurant(place=p1, serves_hot_dogs=True, serves_pizza=False)
>>> r.save()
>>> r.place
<Place: Demon Dogs the place>
>>> p1.restaurant
Thus, in their example, they simply call p1.restaurant without explicitly defining this name. Django assumes the name starts with a lowercase. What happens if the name of an object has more than one word, for example FancyRestaurant?
Side note. I am trying to extend a User object this way. Maybe a problem?
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