Sort ls-l owners on Unix

Question

I want to sort the owners alphabetically from calling ls -l and cannot figure out how to do this. I know something like ls-l | sort will sort the file name, but how do I sort the owners in order?

Answer 1

The owner is the third field, so use -k 3:

ls -l | sort -k 3

You can extend this idea to sort based on other fields, and you can have several options -k. For example, perhaps you want to sort by owner, and then size in descending order:

ls -l | sort -k 3,3 -k 5rn

Answer 2

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ls -l | tr -s ' ' | cut -d ' ' -f 3 | sort | uniq

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Answer 3

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ls -l | cut -d ' ' -f 3 | sort | uniq

Answer 4

:

ls -l | awk '{print $3, $4, $8}' | sort

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ls -l | awk '{print $3, $4, $0}' | sort

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