Is it possible to have one version of machine code for all template function template arguments?

Question

Some people here said that this is not possible, and some people here said that maybe there is one version of the machine code for all the various arguments to the template function template, so I thought it would be useful to open a thread on this specific issue if there is no such possibility, so that she, if any, in what situations can we count on this? An example that was specifically addressed in both of the streams mentioned is given below:

template<size_t num>    
struct Elements{
 public:
  SomeType elements[num];
};

template<size_t num>
void print(const Elements<num> & elements,size_t size){
 //all instances do exactly same thing and with regard to Size that determines the size of object
}

and, of course, they are also passed by version of the values:

template<size_t num>
void print(const Elements<num> elements,size_t size){
 //all instances do exactly same thing and with regard to Size that determines the size of object
}

Answer 1

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template<typename T>
GetLowBit( T foo ) { return T & 1; }

GetLowBit<unsigned long>(ulong x); // compiles to "li r4, 1 ; and r3, r3, r4 ; blr "
GetLowBit<signed long>(long x); // also compiles to "li r4, 1 ; and r3, r3, r4 ; blr "

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class A
{ 
  virtual void nothing() {};
}

class B
{
   virtual void empty() {};
}

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Answer 2

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Answer 3

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