The number of increments sed

Question

I would like to substitute some text with an extra value. Given the xx file:

<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>

and sed command:

for n in seq 3;do sed -e 's/<RecordID>\d/<RecordID>'`echo $n`'/' xx; done

The command echo $ndoes not receive an increment.

Tried also:

n=1; sed -e 's/<RecordID>/<RecordID>'`echo $n ;let n=$n+1`'/g' xx

but without success.

Given only sed (no awk or perl), how can I increase the RecordID field, as in:

<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>2</RecordID>
<outro>dfdfd</outro>
<RecordID>3</RecordID>
<outro>dfdfd</outro>

Answer 1

while read line; do n=$((++n)) &&  echo $line|sed -e 's/[0-9]/'$(($n))'/' ; done < patt

Answer 2

Despite the statement in the question that Perl and Awk cannot be used, the answers presented so far indicate that sedit is not the right tool for this task. Both answers that I see only work with an extremely limited data set and only work with extremely small data sets.

sed, . , , (: 3 4, 2 3, 3 4).

Perl Python, .

perl -e 's{<RecordID>(\d+)</RecordID>}{$n=$n+1; "<RecordID>$n</RecordID>"}e'

: " ". sed - , ( , ). .

Answer 3

-, sed \d. [0-9] [[:digit:]].

-, for n in seq 3 n "seq" "3". for n in $(seq 3) ( Bash) for n in {1..3}.

-, . sed -i ( ), sed ... xx > xx.tmp && mv xx.tmp xx.

-, , .

, , :

for n in $(seq 3); do sed -e $(($n*2))'s/<RecordID>[[:digit:]]/<RecordID>'$n'/' xx > xx.tmp && mv xx.tmp xx; done

Answer 4

sed - , , . - , , script sed. , . , , - .