Algorithm for dividing a self-intersecting Path2D into multiple disjoint paths?

Question

I need to get rid of self-intersections in the form. The shape is built from an array of points, so all segments of this shape are lines. ( only , no curves and arcs)

Previously, I tried to create Path2D from these points, build an Area from it, and then using PathIterator I created several Path2Ds that were somehow subpaths of the previous path, and therefore were not self-intersecting. But this does not work for some paths - self-intersections still remain.

So, could you point me to some place where I can find a good algorithm to accomplish such a thing?

Edit: I haven’t found anything useful anywhere, so I wrote my own algorithm. See Answers.

Answer 1

If this Areadoes not work for you, you can try using GLUtessellator to decompose your Shapetriangles into a set or (using the option GL_LINE_LOOP) only boundary edges.

Answer 2

So, since I could not find anything like this on the Internet, I wrote my own algorithm.

It can be insanely inefficient, but for me it works fast enough.

There he is:

/**
 * Takes a polygon, defined by a list of lines, and splits it into several
 * paths on points of intersection. If non-self-intersected path is passed in,
 * the same path is returned.
 * @param path
 * @return
 */
public static List<List<Line2D>> splitPath(List<Line2D> lines) {
    List<List<Line2D>> splitted = new ArrayList<List<Line2D>>();
    // find intersections.
    loop1:
    for (Line2D l1 : lines) {
        for (Line2D l2 : lines) {
            if (l1 == l2) continue;
            Point2D intr;
            if ((intr = linesIntersect(l1, l2)) != null) {
                // creating two splitted subpaths
                int i1 = lines.indexOf(l1);
                int i2 = lines.indexOf(l2);

                List<Line2D> subpath1 = new ArrayList<Line2D>();
                subpath1.addAll(lines.subList(0, i1));
                subpath1.add(new Line2D.Double(l1.getP1(), intr));
                subpath1.add(new Line2D.Double(intr, l2.getP2()));
                subpath1.addAll(lines.subList(i2 + 1, lines.size()));
                splitted.addAll(splitPath(subpath1));

                List<Line2D> subpath2 = new ArrayList<Line2D>();
                subpath2.add(new Line2D.Double(intr, l1.getP2()));
                subpath2.addAll(lines.subList(i1 + 1, i2));
                subpath2.add(new Line2D.Double(l2.getP1(), intr));
                splitted.addAll(splitPath(subpath2));
                break loop1;
            }
        }
    }
    if (splitted.size() > 0) {
        return splitted;
    } else {
        return Collections.singletonList(lines);
    }
}

/**
 * Returns point of intersection of this line segments.
 * @param l1
 * @param l2
 * @return
 */
public static Point2D linesIntersect(Line2D l1, Line2D l2) {
    if (l1.getP1().equals(l2.getP2()) || l1.getP2().equals(l2.getP1())) return null;
    Point2D inter = lineIntersection(l1, l2);
    if (inter == null) return null;
    double infS = HEADER.infS;
    double x = inter.getX();
    if (((l1.getX1() > l1.getX2()) ? (x + infS > l1.getX2() && x - infS < l1.getX1()) : (x - infS < l1.getX2() && x + infS > l1.getX1())) &&
           ((l2.getX1() > l2.getX2()) ? (x + infS > l2.getX2() && x - infS < l2.getX1()) : (x - infS < l2.getX2() && x + infS > l2.getX1()))) {
        return inter;
    } else {
        return null;
    }
}

/**
 * Returns point of lines intersection, or null if they are parallel.
 * @param l1
 * @param l2
 * @return
 */
public static Point2D lineIntersection(Line2D l1, Line2D l2) {
    double a1 = l1.getY2() - l1.getY1();
    double b1 = l1.getX1() - l1.getX2();
    double c1 = a1*l1.getX1() + b1*l1.getY1();
    double a2 = l2.getY2() - l2.getY1();
    double b2 = l2.getX1() - l2.getX2();
    double c2 = a2*l2.getX1() + b2*l2.getY1();
    double det = a1*b2 - a2*b1;
    if (det != 0) {
        double x = (b2*c1 - b1*c2)/det;
        double y = (a1*c2 - a2*c1)/det;
        return new Point2D.Double(x, y);
    } else {
        // lines are parallel
        return null;
    }
}

Answer 3

/ , - , GEOS, . GEOS Python/Django, JTS (Java Topology Suite), Python psuedo-.

, UNION , ( ), , :

line  = LineString(list_of_lines_x_y_coordinates)
# union with first point splits into MultiLineString containing segments
segments = line.union(line[0])