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Reference syntax string (City, State Zip) with JavaScript

I have a line with the following format:

City, ZIP

I would like to get City and State from this line.

How can I do this using JavaScript? edit: note that it does not mention that it already has a zip code when it gets here, if that helps you solve ~~ drachenstern

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var address = "San Francisco, CA 94129";

function parseAddress(address) {
    // Make sure the address is a string.
    if (typeof address !== "string") throw "Address is not a string.";

    // Trim the address.
    address = address.trim();

    // Make an object to contain the data.
    var returned = {};

    // Find the comma.
    var comma = address.indexOf(',');

    // Pull out the city.
    returned.city = address.slice(0, comma);

    // Get everything after the city.
    var after = address.substring(comma + 2); // The string after the comma, +2 so that we skip the comma and the space.

    // Find the space.
    var space = after.lastIndexOf(' ');

    // Pull out the state.
    returned.state = after.slice(0, space);

    // Pull out the zip code.
    returned.zip = after.substring(space + 1);

    // Return the data.
    return returned;
}

address = parseAddress(address);

This is probably better than using regular expressions and String.split (), since it takes into account that state and city can have spaces.

EDIT: Bug fix: it includes only the first word of verbose state names.

.: D

function parseAddress(a) {if(typeof a!=="string") throw "Address is not a string.";a=a.trim();var r={},c=a.indexOf(',');r.city=a.slice(0,c);var f=a.substring(c+2),s=f.lastIndexOf(' ');r.state=f.slice(0,s);r.zip=f.substring(s+1);return r;}
+10

. :

var parts = "City, State ZIP".split(/\s+/); // split on whitespace
var city = parts[0].slice(0, parts[0].length - 1); // remove trailing comma
var state = parts[1];
var zip = parts[2];

, :

var parts = "san fran bay, new mex state 666666".split(/\s+|,/),
    partition = parts.indexOf(""),
    city = parts.slice(0, partition).join(" "),
    state = parts.slice(partition + 1, -1).join(" "),
    zip = parts.pop();

, , :

var city, statezip, state, zip, parts;
[city, statezip] = "Spaced City, New Mexico ZIP".split(/,\s*/);
parts = statezip.split(/\s+/);
zip = parts.pop();
state = parts.join(" ");

, .

+2

, regex , . , , , -, :

    var str = "New York, NY 20101";
    var cityAndRest = str.split(',');
    var city = cityAndRest[0];
    var stateAndZip = cityAndRest[1].trim().split(' ');
    var state = stateAndZip[0];
    var zip = stateAndZip[1];
+1

: .

, 5 10 . - , . , , . , , 10 (city #####), (12345-6789), , 5 5 + 4 zip. . (city-du-lac 12345 -lac 12345)

, . . , , , , . , Washington DC Washington, DC. , .

, , , .

function IsNumeric(n) {
  return !isNaN(parseFloat(n)) && isFinite(n);
}

var addr = 'New York City, New York 10101';
//var addr = 'San Bernadino, CA 11111';
function getCityStateZip(addr){
  var city; var state;var zip;
  city = ''; state = ''; zip = '';
  var addrLen = addr.length;
  if ( IsNumeric( addr.substring(addrLen - 1) ) ) {
    //contains a zipcode - just a sanity check
    //get last 10 characters for testing easily
    var lastTen = addr.substring( addrLen - 10 );
    if ( lastTen.indexOf('-') > 0 && ( lastTen.indexOf(' ') == -1 ) ) {
      //found a hyphen and no space (matches our complex rule for zipcodes)
      zip = lastTen;
    } else {
      zip = addr.substring( addrLen - 5 ); //assume a basic 5 zip code
    }
  }
  var zipLen = zip.length;
  addrLen = addrLen - zipLen - 1;
  addr = addr.substring(0, addrLen ); //remove the chars we just moved into zip

  var lastComma = addr.lastIndexOf(',');
  if ( lastComma == -1 ) {
    //you have a problem, how do you want to handle it?
  }
  city = addr.substring(0,lastComma); //skip the comma itself, yes?
  state = addr.substring(lastComma + 2);
  return { 'city':city,'state': state,'zip': zip};
}

getCityStateZip(addr)

IsNumeric js JavaScript - IsNumeric()

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