Your revised question is simple, simple
f @@ {a,b,c,...} == f[a,b,c,...]
where @@is the abbreviation for Apply. Inside {a,b,c}there List[a,b,c](you can see, using FullFormfor any expression), and Applysimply replaces Head, Listwith a new Head, fwhich changes the function. The operation is Applynot limited to lists, in general
f @@ g[a,b] == f[a,b]
Also, look Sequencewho does
f[Sequence[a,b]] == f[a,b]
So, we could do it instead
f[ Sequence @@ {a,b}] == f[a,b]
, , .
: Apply 2 nd , ..
Apply[f, {{a,b},{c,d}}, {1}] == {f[a,b], f[c,d]}
. Apply[fcn, expr,{1}] @@@, , .