Split a word in Ruby for counting

Question

When I split the string "hello world / n" with

"hello world \n".scan(/\w+/)

I get ["hello", "world"]

I would like to consider \ n or \ t as a string.

Answer 1

Do you need something like this?

"hello world \n".scan(/\w+|\n/)

Answer 2

Use not \w+ to count words. It will separate numbers and words using Unicode as follows:

"The floating point number is 13.5812".scan /\w+/
=> ["The", "floating", "point", "number", "is", "13", "5812"]

The same is true for numbers with other type delimiters "12,000".

In Ruby 1.8, the expression w+worked with Unicode, this has changed. If your string contains Unicode characters, the word will also be split.

"Die Apfelbäume".scan /\w+/
=> ["Die", "Apfelb", "ume"]

There are two options.

• . ,

  /\p{Letter}+/
  

• , .

  /\S+/
  

  \S+ /[^ \t\r\n\f]/. , . , , .. .

  . .

Answer 3

\n : , . : \\n.

,

"Hello world \n".split(/ /)

Answer 4

"hello world \n".scan /[\w\n\t]+/

Answer 5

, (, 90- ..)

"hello world \n".split(/[^\w']+/)

Answer 6

You can use the named character class [: cntrl:].

irb(main):001:0> "hello world \n".scan(/\w+|[[:cntrl:]]/)
=> ["hello", "world", "\n"]