How does a variable typed as enum take on a value that goes beyond its elements?

Question

Can someone explain to me how the member of this enum takes on meaning 0?

public enum EnumLogicalOperator
{
    And = 1,
    Or = 2
}

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Answer 1

Whenever you use default(EnumLogicalOperator)or new EnumLogicalOperator(), you will get a null value. In other words, the default value for an element of type enum is always 0. All enumerations will be set to 0 until you set them to something else.

Answer 2

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Answer 3

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Answer 4

: http://msdn.microsoft.com/en-us/library/sbbt4032%28v=vs.80%29.aspx

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Answer 5

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EnumLogicalOperator x = EnumLogicalOperator.Or;

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Answer 6

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Answer 7

An enumeration can have any value based on its base type (Int32 in your case).

EnumLogicalOperator op = (EnumLogicalOperator) 0;
EnumLogicalOperator op = (EnumLogicalOperator) 100;
EnumLogicalOperator op = (EnumLogicalOperator) 900000;
EnumLogicalOperator op = (EnumLogicalOperator) -1;

private EnumLogicalOperator _op; // As a class member, will default to 0

Be sure to use Enum.IsDefined when checking your input conditions and error handling. It is also usually a good idea to include 0 as the value for one of your enum values.

Answer 8

I suggest you include the "Undefined" member with a value of 0, or make your "And" or "Or" a value of 0.