Bad results: time (NULL) and hours ()

Question

#import <stdio.h>
#import <time.h>

int main (void) {

    printf("Clock ticks per second: %d\n", CLOCKS_PER_SEC);
    double check = clock();
    int timex = time(NULL);

    for (int x = 0; x <= 500000; x++) {

        printf(".");

    }
    puts("\n");

    printf("Total Time by Clock: %7.7f\n", (clock() - check) / CLOCKS_PER_SEC );
    printf("Total Time by Time: %d\n", time(NULL) - timex);

    getchar();
}

When I execute the above code, I get results such as:

Total time by hours: 0.0108240

Total time by time: 12

I would like clock () to represent the number as close to time as possible.

The total time stated above was done on a macbook, however the code works fine on my laptop (windows).

The macro CLOCKS_PER_SECOND returns 1000 on a PC, 1,000,000 on a MAC.

Answer 1

clock () on windows returns the wall clock time. clock () on * nixes returns the processor time spent by your program, which will not be much, you are probably blocked when doing I / O here.

Answer 2

printf() functon, , .., .

.

for (long int x = 0; x <= 5000000000; x++) {
    sqrt(2.9999);
}

Answer 3

time()returns a time_t. When you assign it int, it is possible that you will lose information. What happens if you use time_teverywhere?

int main(void) {
    time_t timex = time(0);
    /* ... */
    printf("%d", (int)(time(0) - timex));
}