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Ruby DateTime.Parse local time

I have a date string 20101129220021, so I will use

require 'date'
d = DateTime.parse('20101129220021')

This part is working fine, and I get a date that is in UTC.

My question is, how can I convert this to my local time? I tried many methods, such as extracting the time part with help d.to_timeand manipulating the result, but that did not work. As far as I know, the object is DateTimeimmutable. Can i get help?

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2 answers

You can add a rational percentage based on time zone to get local time.

require 'date'

# Make this whatever your zone is. Using UTC +0300 here.
ZONE = 3

d = DateTime.parse('20101129220021') + Rational(ZONE,24)

d.to_s # => "2010-11-30T01:00:21+00:00"
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irb(main):001:0> require "date"
=> true
irb(main):002:0> d = DateTime.parse('20101129220021')
=> #<DateTime: 2010-11-29T22:00:21+00:00 (70719276007/28800,0/1,2299161)>
irb(main):003:0> d.to_time
=> 2010-11-30 00:00:21 +0200

ruby 1.9.2p180 (2011-02-18)

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