Sort sibling <div> s using jQuery
I hit my head on a problem that has more to do with second-class math than programming. Here: four elements <div>are placed one after another horizontally. When you click one, the script puts it in front. You press another, and also place in front, etc. You get an image. Now I would like to sort the remaining elements <div>(all but the first) using the original order.
Perhaps this picture will clarify the situation:

After step №3 Cshould be placed after B, so it should look like this: D A B C.
Here is a sample code:
<html>
<head>
<title>mixit</title>
<style type="text/css">
.insidebox{
width: 50px;
height: 50px;
line-height: 50px;
margin: 0 0 0 20px;
text-align: center;
float: left;
border: black solid 3px;
font-family: sans-serif;
cursor: pointer;
}
</style>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.0/jquery.min.js"></script>
<script type="text/javascript">
</script>
</head>
<body>
<div id="container">
<div id="a" class="insidebox">A</div>
<div id="b" class="insidebox">B</div>
<div id="c" class="insidebox">C</div>
<div id="d" class="insidebox">D</div>
</div>
</body>
</html>
, , .insertAfter() , ? - , . .
+5
3
, .
var $initial = $('.insidebox');
$('.insidebox').click(function(){
var $this = $(this);
$this.parent()
.prepend($this)
.append( $initial.not(this) );
});
( )
demo http://jsfiddle.net/gaby/Dyafx/
.. . , .
var $initial = $('.insidebox');
$('.insidebox').click(function(){
$(this).parent()
.append( $initial.not(this) );
});
+5