I have an existing SQL query that works fine, as I want it:
$this->db->select('places.*, category.*')
->select('COUNT(places_reviews.place_id) AS num_reviews')
->select('(places_popularity.rating_1 + 2*places_popularity.rating_2 + 3*places_popularity.rating_3 + 4*places_popularity.rating_4 + 5*places_popularity.rating_5)/(places_popularity.rating_1 + places_popularity.rating_2 + places_popularity.rating_3 + places_popularity.rating_4 + places_popularity.rating_5) AS average_rating')
->from('places')
->join('category', 'places.category_id = category.category_id')
->join('places_reviews', 'places_reviews.place_id = places.id', 'left')
->join('places_popularity', 'places_popularity.place_id = places.id', 'left')
->where('places.category_id', $category_id)
->group_by('places.id')
->limit($limit, $offset)
->order_by($sort_by, $sort_order);
However, now I want to add a LIKE clause to the query, adding another line to the above to get:
$this->db->select('places.*, category.*')
->select('COUNT(places_reviews.place_id) AS num_reviews')
->select('(places_popularity.rating_1 + 2*places_popularity.rating_2 + 3*places_popularity.rating_3 + 4*places_popularity.rating_4 + 5*places_popularity.rating_5)/(places_popularity.rating_1 + places_popularity.rating_2 + places_popularity.rating_3 + places_popularity.rating_4 + places_popularity.rating_5) AS average_rating')
->from('places')
->join('category', 'places.category_id = category.category_id')
->join('places_reviews', 'places_reviews.place_id = places.id', 'left')
->join('places_popularity', 'places_popularity.place_id = places.id', 'left')
->where('places.category_id', $category_id)
->like('places.name', $term)
->group_by('places.id')
->limit($limit, $offset)
->order_by($sort_by, $sort_order);
However, this gives me inaccurate results. For example, when I allow the search for the string $ term = "hong", and I have 3 rows where the column "name" matches "hong", i.e. (Hong Kong cafe, Hong Kong cafe, Ramen Hong), I will only receive (Hong Kong cafe, Hong Kong cafe). Now, if $ term = "hong kong", I get only one from the "Hong Kong cafe", and not both.
Another riddle me even more! There is a line called Dozo. When $ term = 'dozo', the result is not returned!
, ?
SQL
, 1
SELECT `places`.*, `category`.*, COUNT(places_reviews.place_id) AS num_reviews, (places_popularity.rating_1 + 2*places_popularity.rating_2 + 3*places_popularity.rating_3 + 4*places_popularity.rating_4 + 5*places_popularity.rating_5)/(places_popularity.rating_1 + places_popularity.rating_2 + places_popularity.rating_3 + places_popularity.rating_4 + places_popularity.rating_5) AS average_rating FROM (`places`) JOIN `category` ON `places`.`category_id` = `category`.`category_id` LEFT JOIN `places_reviews` ON `places_reviews`.`place_id` = `places`.`id` LEFT JOIN `places_popularity` ON `places_popularity`.`place_id` = `places`.`id` WHERE `places`.`category_id` = 1 AND `places`.`name` LIKE '%Dozo%' GROUP BY `places`.`id` ORDER BY `average_rating` desc LIMIT 1, 3
UPDATE
. , LIMIT. !