Geek Answers Handbook

SQL Get the first occurrence of the 15th for a date

I need to write a function or SP that will return the first appearance of the 15th. For example, if I pass the date on May 8, then it should return on May 15. If I pass on May 30th, then he must return on June 15th.

+5
source share
8 answers

One of the methods

   DECLARE @d DATETIME
    SELECT @d = '20110508'
    --SELECT @d = '20110530'


    SELECT  CASE WHEN DAY(@d)  > 15 
    THEN  dateadd(mm, datediff(mm, 0, @d)+1, 0) + 14
    ELSE dateadd(mm, datediff(mm, 0, @d)+0, 0)+ 14 end
+4
source

What about:

create function udf_getNextDate(@base datetime, @day int) returns datetime as begin
    set @base = case when day(@base) > @day         
            then dateadd(month, 1, @base)
        else @base
    end
    return dateadd(day, -day(@base) + @day, @base)
end

select 
  dbo.udf_getNextDate('08 may 2011', 15),
  dbo.udf_getNextDate('30 may 2011', 15),
  dbo.udf_getNextDate('16 dec 2011', 15),
  dbo.udf_getNextDate('01 may 2011', 15)

2011-05-15 00:00:00.000 
2011-06-15 00:00:00.000 
2012-01-15 00:00:00.000 
2011-05-15 00:00:00.000
+3
source

:

Declare @d datetime

Set @d = getdate()


Select  Case 
            When    DateDiff(Day, Day(@d), 15) < 0 then 
                    DateAdd(month, 1, DateAdd(Day, DateDiff(Day, Day(@d), 15), @d))
            Else    DateAdd(Day, DateDiff(Day, Day(@d), 15), @d) 
        End as [Next15th]
+1

create function Get15th(@date datetime)
returns datetime 
as
begin
declare @resultdate datetime
declare @y int
declare @m int
declare @d int
set @y = datepart(year,@date)
set @m = datepart(month,@date)
set @d = datepart(day,@date)
if( @d<=15)
set @resultdate =cast((str(@y)+'-'+str(@m)+'-15') as datetime)
else
set @resultdate =cast((str(@y)+'-'+str(@m+1)+'-15') as datetime)
return  @resultdate 
end
+1

...

, , 15- , ...

DATEADD(MONTH, DATEDIFF(MONTH, 14, Created) + 1, 14)

DATEDIFF MONTH, , , ;)

DATEADD(MONTH, DATEDIFF(MONTH, 0, Created - 15) + 1, 14)

0

select, (: @mydate)

    declare @mydate datetime
           , @first15th datetime
    set @mydate = convert(datetime,'2011/05/29 11:14:20.334')
    set @first15th = 
        (select
          dateadd(
           day,
           15 - day( dateadd ( day, 
                               day(@mydate) - (day(@mydate)-15) , 
                               @mydate )
           ),
           dateadd ( day, 
                     day(@mydate) - (day(@mydate)-15) , 
                     @mydate)
        )
     select @first15th //for 2011/05/29 11:14:20.334 => 2011/06/15 11:14:20.334
                       //for 2011/05/09 11:14:20.334 => 2011/05/15 11:14:20.334

SP .

0

- :

declare
  @date       datetime ,
  @target_day int

set @date       = 'June 16, 2009'
set @target_day = 15

select date      = @date ,
       next_date = case when day(@date) <= @target_day
                     then dateadd(day,15-day(@date),@date)
                     else dateadd(day,15,dateadd(month,1,dateadd(day,-day(@date),@date)))
                   end

​​, , , SQL Server -.

0

DATEADD(Day, DATEDIFF(Day, 15, Created), 0) AS CreatedDay

http://improve.dk/archive/2006/12/13/sql-server-datetime-rounding-made-easy.aspx

, ,

: ... . Dems answer

-1

More articles:


All Articles