Determine where activation occurs when the form is deactivated

Question

Does anyone know how to determine which window will receive focus when the form is deactivated?

Answer 1

I have found the answer. Instead of subscribing to activated and deactivating events, process the WM_ACTIVATE message (used for both activation and deactivation) in WndProc. Since it reports that the handle of the window to be activated, I can compare this handle with the handles of my forms and determine if the focus on any of them changes.

const int WM_ACTIVATE = 0x0006;
const int WA_INACTIVE = 0;
const int WA_ACTIVE = 1;  
const int WA_CLICKACTIVE = 2;  

protected override void WndProc(ref Message m)  
{  
    if (m.Msg == WM_ACTIVATE)  
    {  
         // When m.WParam is WA_INACTIVE, the window is being deactivated and
         // m.LParam is the handle of the window that will be activated.

         // When m.WParam is WA_ACTIVE or WA_CLICKACTIVE, the window is being 
         // activated and m.LParam is the handle of the window that has been 
         // deactivated.
    }  

    base.WndProc(ref m);  
} 

: , (, ).

NativeWindow . :

public class Popup : Form
{
    const int WM_ACTIVATE = 0x0006;
    const int WA_INACTIVE = 0;
    private ParentWindowIntercept parentWindowIntercept;

    public Popup(IntPtr hWndParent)
    {
        this.parentWindowIntercept = new ParentWindowIntercept(hWndParent);
    }

    private class ParentWindowIntercept : NativeWindow
    {
        public ParentWindowIntercept(IntPtr hWnd)
        {
            this.AssignHandle(hWnd);
        }

        protected override void WndProc(ref Message m)
        {
            if (m.Msg == WM_ACTIVATE)
            {
                if ((int)m.WParam == WA_INACTIVE)
                {
                    IntPtr windowFocusGoingTo = m.LParam;
                    // Compare handles here
                }
            }

            base.WndProc(ref m);
        } 
    }
}

Answer 2

, Form.ActiveForm.

Answer 3

( Intellisense VS).

WndProc , , .

An alternative approach is to use a timer and validate Form.ActiveControl after a short amount of time. Thus, the code is encapsulated better, inside the editor control or popup form .

Form _txPopup;

// Subscribe whenever convenient
public void IntializeControlWithPopup(Form _hostForm)
{
    _hostForm.Deactivate + OnHostFormDeactivate;
}

Timer _deactivateTimer;
Form _hostForm;
void OnHostFormDeactivate(object sender, EventArgs e)
{
    if (_deactivateTimer == null) 
    {
        _mainForm = sender as Form;
        _deactivateTimer = new Timer();
        _deactivateTimer.Interval = 10;
        _deactivateTimer.Tick += DeactivateTimerTick;
    }
    _deactivateTimer.Start();
}

void  DeactivateTimerTick(object sender, EventArgs e)
{
    _deactivateTimer.Stop();
    Form activeForm = Form.ActiveForm;
    if (_txPopup != null && 
        activeForm != _txPopup && 
        activeForm != _mainForm) 
    { 
        _txPopup.Hide(); 
    }
}