How does fgets work inside?

Question

Well, this is the main question, but I seem to be pretty confused.

#include<stdio.h>
int main()
{
char a[100];
printf("Enter a string\n");
scanf("%s",a);
}

Basically, this is what I want to achieve. If I enter a line

James Bond

then I want this to be stored in array a. But the problem is that only the words of James are stored in the empty space between the letters. So how can I solve this problem.

UPDATE
After the answers below, I understand that fgets () would be a better choice. I want to know the inner workings of fgets, why it can store a string with a space where scanf cannot do the same.

Answer 1

This is what you need?

• freeBSD: http://www.freebsd.org/cgi/cvsweb.cgi/src/lib/libc/stdio/fgets.c?rev=1.14.14.1;content-type=text%2Fplain
• : https://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=7425&lngWId=3
• OWP () http://www.koders.com/c/fid042417FA231704B84308A66E1B82EADEDAB22051.aspx
• ReactOS http://www.koders.com/c/fidEB3507945463053CEFCD518EA0CDFF9EB78E24C9.aspx?s=fgets.c#L1

( ) , \n EOF, maxSize...

Answer 2

scanf . fgets, , :

fgets(a, 100, STDIN);

100 ( \n) .

gets, .

Answer 3

scanf (, , ,...).

, " 5 42 -100" scanf("%d%d%d"), %d . %s.

, , %%, %[ %c (, , %n)

char input[] = " hello world";
char buf[100];
sscanf(input, "%8c", buf); /* buf contains " hello w" */
sscanf(input, "%8[^o]", buf); /* buf contains " hell" */

fgets , , .

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Open Group Issue 7 -

Answer 4

get (a)/fgets (a, sizeof (a), stdin) sscanf().

Answer 5

Try fgets () :

char a[100];
printf("Enter a string\n");
fgets(a, sizeof(a), STDIN);

To learn more about STDIN, check this out .