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Try using resources in Java 7?

In the new Try-with-Resources syntax in Java 7, do I need to worry about the order of resources?

try (InputStream in = loadInput(...); // <--- can these be in any order?
     OutputStream out = createOutput(...) ){
    copy(in, out);
}
catch (Exception e) {
    // Problem reading and writing streams.
    // Or problem opening one of them.
    // If compound error closing streams occurs, it will be recorded on this exception 
    // as a "suppressedException".
}
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4 answers

Order matters if and only if it matters when using the usual {create resources} syntax. Resources that were acquired first will be closed last. See techno for more details .

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Actually, the order doesn't matter. Ideally, if the resources are not connected to each other, you can open them in any order, and they can be closed in any order.

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In your example, the order definitely doesn't matter. You only use resources in the try block, where both are already available. If you connect to the database, order or open-ended questions, but I would create a separate method to cover this. This method should implement AutoClosable and override the close () method. Although close () throws an exception, your method is not required.

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