Where is function overriding done?

Question

Where in the process of creating the program, the compiler, linker, etc. Is overriding functions and operator overloading?

I am particularly interested where this is done in C ++, Ruby and Python.

Answer 1

The overload function is (at least in C ++) internally processed inside the compiler. The idea is that the code that the compiler ultimately generates will be hard-coded to call the corresponding function, as if all functions had different names, and you called a function that is unique to the arguments. More generally, in most compiled languages ​​that support overloading, overload resolution is performed at compile time, and the emitted code always calls the specified function. For example, Haskell supports compile-time overloading in this way.

Operator overloading is a special case of general overloading, so it is usually handled the same way.

(, , ) , , . , , .

, , . , .

Answer 2

++ , , , . ++ , , +, -, * .., , operator, . , , operator+ ,

my_type operator+(const my_type& lhs, const my_type& rhs);

operator+ , operator+, ++ . , C ++ , .

, C, , , C- , .

Answer 3

Python is not bound / not compiled, it is interpreted. Thus, normal redefinition is performed when analyzing class sources. Of course, because of the dynamic nature, you can always redefine during operation. I believe that alternative implementations using byto-code compilation do this at compile time.

I also believe that the above is true for Ruby.