What does "Ambiguous output redirection" mean?

Question

I have a PHP script that I want to call in some form action.

This command works great:

/usr/local/bin/php -q script.php > /dev/null 2>&1 &

But things go wrong when I add arguments to the command:

/usr/local/bin/php -q script.php --var=value > /dev/null 2>&1 &

it returns "Undefined output redirection".

I read this article http://www.xaprb.com/blog/2006/06/06/what-does-devnull-21-mean/ and tried almost everything as far as I can understand, and still don't know how it is fix it.

Please help me.

+5

Gohar sultan Aug 2 '11 at 11:55

3 answers

Karoly Horvath · Answer 1 · 2011-08-02T12:18:42+0000

I assume that you are using csh or one of its variants, use:

... >&/dev/null

Kris Ogirri · Answer 2 · 2011-09-23T12:55:49+0000

:

/usr/local/bin/php -q script.php --var=value > &1 &

.

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, - . , AiX, root, , - , " ".

STDERR, STDOUT, , - .

Jorrit Schippers · Answer 3 · 2011-08-02T12:20:24+0000

:

/usr/local/bin/php -q script.php --var=value > /dev/null 2>/dev/null &