Geek Answers Handbook

Spring Plugin Authentication Failure Error

EDITED HEADER: more related to the real issue

I am trying to set spring security for my test application

i installed the plugin, created user classes and roles;

put it in UrlMappings.groovy;

        "/login/$action?"(controller: "login")
    "/logout/$action?"(controller: "logout")

then I put the user in bootstrap as follows:

import org.project.auth.Role
import org.project.auth.User
import org.project.auth.UserRole;

class BootStrap {
    def springSecurityService
    def init = { servletContext ->
        def userRole = Role.findByAuthority('ROLE_USER') ?: new Role(authority: 'ROLE_USER').save(failOnError: true,flush:true)
        def adminRole = Role.findByAuthority('ROLE_ADMIN') ?: new Role(authority: 'ROLE_ADMIN').save(failOnError: true,flush:true)

        def adminUser = User.findByUsername('admin') ?: new User(

                username: 'admin',

                password: springSecurityService.encodePassword('admin'),

                enabled: true).save(failOnError: true,flush:true)

        print User.count()          

        if (!adminUser.authorities.contains(adminRole)) {
                    print "TEST"
            UserRole.create adminUser, adminRole,true
        }
    }
    def destroy = {
    }
}

this print User.count () returns 1, so I know that the user is created, printing "TEST" also works, so I know that he is in the if block, but when I start the server, it fails with

Sorry, we were not able to find a user with that username and password.

I am using Grails 2.0.0.M1, do you think this could be a problem?

+5
source share
2 answers

2.0 . , , , springSecurityService. password: springSecurityService.encodePassword('admin') password: 'admin', .

, , , . Config.groovy log4j:

debug 'org.springframework.security'

, , if (!adminUser.authorities.contains(adminRole)) { if (!UserRole.findByUserAndRole(adminUser, adminRole)) { `

+10

More articles: