I have two classes int_t, uint_tboth the type of the signed and unsigned type:
template <typename lo_t> struct uint_t;
template <typename hi_t, typename lo_t>
struct int_t
{
lo_t lo;
hi_t hi;
int_t() : hi(0), lo(0) {}
int_t(int value) : lo(value), hi(value<0? -1: 0) {}
int_t(unsigned value) : lo(value), hi(0) {}
int_t(const uint_t<lo_t>&);
};
template <typename hi_lo>
struct uint_t
{
hi_lo lo, hi;
uint_t() : lo(0), hi(0) {}
uint_t(int value) : lo(value), hi(value<0? -1: 0) {}
uint_t(unsigned value) : lo(value), hi(0) {}
template<typename hi_t>
uint_t(const int_t<hi_t, hi_lo>& value) : hi(value.hi), lo(value.lo) {}
};
template <typename hi_t, typename lo_t>
int_t<hi_t, lo_t>::int_t(const uint_t<lo_t>& value) : hi(value.hi), lo(value.lo)
{}
Since I want them to work just like built-in types, I defined a conversion operator from one to another so that I can write code like the following and it still works:
typedef int_t<int, unsigned> int64;
typedef uint_t<unsigned> uint64;
int64 a = 1000;
uint64 b = a;
uint64 x = 512;
int64 y = x;
Now the only problem is converting from a higher or lower precision type int_tto another, so I declared a constructor with comments to do this, but I don’t know what to write in it?
Here is an example that I used to check the result of this constructor:
typedef int_t<int, unsigned> int64;
typedef uint_t<unsigned> uint64;
typedef int_t<int64, uint64> int128;
typedef uint_t<uint64> uint128;
int64 a = 1024;
int128 b = a;
int128 x = 100;
int64 y = x;
source
share