PostBackUrl Button - , , PreviousPage:
Button oButton = new Button;
oButton.Text = "NextPage";
oButton.PostBackUrl = "Redirect.aspx";
, , TextBox txtMyInput, ( , ):
void Page_Load(object sender, EventArgs e)
{
string myInputText = ((TextBox)PreviousPage.FindControl("txtMyInput")).Text;
}
, , .
. Button.PostBackUrl Property.