C: Memory layout for executing program C

Question

I wanted to know how the kernel provides memory for a simple C program.

For instance:

#include<stdio.h> 
#include<malloc.h> 
int my_global = 10 ; 
main() 
{ 
char *str ; 
static int val ; 
str = ( char *) malloc ( 100 ) ; 
scanf  ( "%s" , str ) ;
printf( " val:%s\n",str ) ;
free(str) ;
return 1 ;
}

See. In this program, I used static, global and malloc to allocate dynamic memory. So, how will the memory be laid out ...? Any of them gives me a url that will have detailed information about this process.

Answer 1

Basically, in C programs created for the target ELF (Executable and Bound format), such as those built on Linux, there is a standard memory layout that is created. Similar layouts probably exist for other architectures, but I don’t know enough to tell you more about them.

Layout:

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Answer 2

wikipedia.

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Answer 3

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Answer 4

, C-, , C.

http://www.firmcodes.com/memory-layout-c-program-2/