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How to delete all files that were recently created in a directory on Linux?

I parsed something into a directory that already contains a lot of things. Instead, I wanted to break up into a separate directory. Now there are too many files to distinguish. However, the files that I unpacked were created just now (right?), And the source files were not changed for a long time (at least one day). Is there a way to delete only these raw files based on their creation information?

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4 answers

Tar usually restores file timestamps, so time filtering is unlikely to work.

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tar tf file.tar --quoting-style=shell-always |xargs rm -i

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. -mtime -1-type f | xargs rm

. -mtime -1-type f | xargs echo

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tar -tf file.tar | egrep '^(\./)?[^/]+(/)?$' | egrep -v '^\./$' | tr '\n' '\0' | xargs -0 rm -r

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mkdir foodir
cd foodir
tar -xf ../file.tar
for file in *; do rm -rf ../"$file"; done

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mkdir foodir
cd foodir
tar -xf ../file.tar
find . -mindepth 1 -maxdepth 1 -print0 | xargs -0 sh -c 'for file in "$@"; do rm -rf ../"$file"; done' junk

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tar -tf file.tar | egrep '^(\./)?[^/]+(/)?$' | grep -v '^\./$' | tr '\n' '\0' | xargs -0 bash -c 'for fname in "$@"; do fname="$(echo -ne "$fname")"; echo -n "$fname"; echo -ne "\0"; done' junk | xargs -0 rm -r
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tar  -tf ../test/bob.tar --quoting-style=shell-always | sed -e "s/^\(.*\/\)'$/rmdir \1'/; t; s/^\(.*\)$/rm \1/;" | sort | bash

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tar  -tf ../test/bob.tar --quoting-style=shell-always | sed -e "s/^\(.*\/\)'$/rmdir \1'/; t; s/^\(.*\)$/rm \1/;" | sort

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