What's wrong with defining this type of Struct

Question

I defined my structure as follows:

struct Test
{
    private string assayName;
    public string AssayName { get; set; }

    private string oldUnitName;
    public string OldUnitName { get; set; }

    private string newUnitName;
    public string NewUnitName { get; set; }

    public Test(string name, string oldValue, string newValue)
    {
        assayName = name;
        oldUnitName = oldValue;
        newUnitName = newValue;
    }

}

but this gives me the following error:

"Error 13 The backup field for the automatically implemented property 'EnterResults.frmApplication.Test.NewUnitName' must be fully assigned before control returns to the caller. Consider calling the default constructor from the constructor initializer."

Answer 1

Well, there are two problems:

1. Using automatic properties, but then also providing fields, there is no wiring between them.

2. , , . . , :

struct Test
{
    public Test(string name, string oldValue, string newValue)
        : this()
    {
        AssayName = name;
        OldUnitName = oldValue;
        NewUnitName = newValue;
    }

    public string AssayName { get; private set; }
    public string OldUnitValue { get; private set; }
    public string NewUnitValue { get; private set; }
}

Answer 2

. :

struct Test 
{ 
    public string AssayName { get; set; } 
    public string OldUnitName { get; set; } 
    public string NewUnitName { get; set; } 

    public Test(string name, string oldValue, string newValue) : this()
    { 
        AssayName = name; 
        OldUnitName = oldValue; 
        NewUnitName = newValue; 
    } 
} 

, . , , , :)

", " - . , , . .

Answer 3

private assayName, oldUnitName newUnitName. :

public Test(string name, string oldValue, string newValue)
{
    AssayName = name;
    OldUnitName = oldValue;
    NewUnitName = newValue;
}

Answer 4

You try to create an automatically implemented property , but you define "fallback fields" (which are not explicitly used), and then you assign values ​​to those supporting fields in your constructor and leave your properties completely untouched.

Answer 5

You can also call the default constructor:

public Test(string name, string oldValue, string newValue) : this() 
{
   assayName = name;
   oldUnitName = oldValue;
   newUnitName = newValue;
}

Look here