I have been trying to solve the problem of YUV422 in RGB conversion for about a week. I visited many different sites and received different formulas from each. If anyone has any suggestions, I would be happy to hear about them. The formulas below give me an image with a common or purple or green tint in them. From now on, I could not find a formula that allows me to return the correct RGB image. I have all my pieces of code below.
for(int i = 0, j=0; i < 1280 * 720 * 3; i+=6, j+=4)
{
BYTE Cr = pData[j+3] - 128;
BYTE Cb = pData[j+1] - 128;
int R1 = clamp((298 * (pData[j] - 16) + 409 * (pData[j+3] - 128) + 128) >> 8, 0, 255), R2 = clamp((298 * (pData[j+2] - 16) + 409 * (pData[j+3] - 128) + 128) >> 8, 0, 255);
int G1 = clamp((298 * (pData[j] - 16) - 100 * (pData[j+1] - 128) - 208 * (pData[j+3] - 128) + 128) >> 8, 0, 255), G2 = clamp((298 * (pData[j+2] - 16) - 100 * (pData[j+1] - 128) - 208 * (pData[j+3] - 128) + 128) >> 8, 0, 255);
int B1 = clamp((298 * (pData[j] - 16) + 516 * (pData[j+1] - 128) + 128) >> 8, 0, 255), B2 = clamp((298 * (pData[j+2] - 16) + 516 * (pData[j+1] - 128) + 128) >> 8, 0, 255);
m_RGB->imageData[i] = (char)R1;
m_RGB->imageData[i+1] = (char)G1;
m_RGB->imageData[i+2] = (char)B1;
m_RGB->imageData[i+3] = (char)R2;
m_RGB->imageData[i+4] = (char)G2;
m_RGB->imageData[i+5] = (char)B2;
}
Any help is greatly appreciated.
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