Python for each module and package

Question

I am trying to structure my application in Python. Coming back from C # / Java background, I like the approach of one class to the file. I would like my project tree to look like this:

[Service]
    [Database]
        DbClass1.py
        DbClass2.py
    [Model]
        DbModel1.py
        DbModel2.py
    TheService.py
[ServiceTests]
    [Database]
        DbClass1Tests.py
        DbClass2Tests.py
    [Model]
        DbModel1Tests.py
        DbModel2Tests.py
    TheServiceTests.py

• Is a single class approach to an OK file in Python?

• Is it possible to create packages / modules in such a way that the packages work like Java packages or .NET namespaces, i.e. in DbModel1Tests.py:

  import Service.Model
  
  def test():
     m = DbModel1()
  

Answer 1

-, 1: , . , , , , , . , Python , .

2: . , , , .

, import Service.Model, m = Service.Model.DBModel1().

, from Service.Model import * ( from Service.Model import DBModel1, ). , : m = DBModel1().

Answer 2

Q1. 1 Python, .

Q2. from Service.Model import * - Service/Model/__init__.py, , , . import * Python

: Python - #/Java. , , $other_language .

, :

• , Python (, )
• , . , DbModel1, /, .
• from Service.Model.DbModel1 import DbModel1 . from service.model import DbModel1: / ( , 1 .)

Answer 3

, . , ( - ).

:

• . __init__.py .
• , : from Service.Model import DbModel , : m = DbModel1.DbModel1Class()

:

• Pythonic ( ). , service.model.dbModel1.DbModel1().
• you can do from Service.Model import DbModel1to directly import a class from a module DbModel1. This can be done by properly setting the content __init__.py(I don’t know how to fine-tune it). More info here