. , node .
, :
def distance(a, b):
return sum((xa - xb) ** 2 for (xa, xb) in zip(a, b))
def clusters(sources, demands):
result = dict((source, []) for source in sources)
for demand in demands:
nearest = min(sources, key=lambda s: distance(s, demand))
result[nearest].append(demand)
return result
, , node, .
, !
user97370